Answer:
f3 = 102 Hz
Step-by-step explanation:
To find the frequency of the sound produced by the pipe you use the following formula:
![f_n=(nv_s)/(4L)](https://img.qammunity.org/2021/formulas/physics/college/64azk31ah9yf68seq63poyf3p1ihjk9qk3.png)
n: number of the harmonic = 3
vs: speed of sound = 340 m/s
L: length of the pipe = 2.5 m
You replace the values of n, L and vs in order to calculate the frequency:
![f_(3)=((3)(340m/s))/(4(2.5m))=102\ Hz](https://img.qammunity.org/2021/formulas/physics/college/9cpd29bp8vflxyfmzkq22pt36ww3fpqljb.png)
hence, the frequency of the third overtone is 102 Hz