Question

A straight wire segment in a circuit is 30.0 m long and moves at 2.0 m/s perpendicular to

a magnetic field. The total resistance of the circuit is 5.0 22. What is the current?

O.12A

O 1.2A

0.122

O 1.20

PLEASE HELP!!!!!!!

Answer 1

I = 12*B (the information about B does not appear in the statement)

Step-by-step explanation:

The motion of the segment of the circuit, in a constant magnetic field makes that opposite charges inside the segment separate of each other. This generate a induced potential difference at the ends of the segment that is given by the following formula:

`\epsilon=vBL` (1)

v: speed of the segment = 2.0m/s

B: magnitude of the magnetic field

`\epsilon=(2.0)(30.0)B=60.0B` (2)

The induced current calculated by replacing the result of (2) in the following formula:

`I=(\epsilon_o)/(R)=(60.0B)/(5.0)=12B` (3)

Then, you only have to replace the value of the magnitude of the magnetic field B in (3) to calculate the current.