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An experiment consists of rolling a standard six-sided die once. Event A is "rolling an even number" and event B is "rolling a 2."

Are the events dependent or independent? Why?


Select the option that correctly answers both questions.

Events A and B are independent, because P(B)=P(B|A)=1/6.

Events A and B are dependent, because P(A)≠P(B|A).

Events A and B are independent, because P(A)=P(B|A)=1/2.

Events A and B are dependent, because P(B)≠P(B|A).

User Berna
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1 Answer

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Answer:

(D)Events A and B are dependent, because P(B)≠P(B|A).

Explanation:

Definition: Two events are independent if


P(A)\cdot P(B)=P(B\cap A)\\$Equivalently:$\\P(B)=(P(B\cap A))/(P(A)) \\P(B)=P(B|A)

An experiment consists of rolling a standard six-sided die once.

Event A is "rolling an even number"

Even numbers are 2,4 and 6


  • P(A)=3/6=1/2

Event B is "rolling a 2."

  • P(B)=1/6


\{A\cap B\}={2}\\P(A\cap B)=1/6

Substitution into
P(B)=(P(B\cap A))/(P(A))

Left Hand Side =1/6

Right Hand Side =(1/6)÷(1/2)=1/3

Since
P(B)\\eq (P(B\cap A))/(P(A)), therefore
P(B)\\eq P(B|A) which makes the events dependent.

User Btbenjamin
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