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An isosceles triangle ABC has its vertices on a circle. If AB =13 cm BC= 13cm and AC= 10cm calculate the height BM of the triangle

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Answer:


BM = 12\,cm

Explanation:

The height BM of the triangle can be determined by using the Pythagorean theorem:


BM = \sqrt{BC^(2)-\left((1)/(2)\cdot AC \right)^(2)}


BM = \sqrt{(13\,cm)^(2)-(5\,cm)^(2)}

The height of the isosceles triangle is:


BM = 12\,cm

User Sam Houston
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