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How many real solutions does the equation 8x^2 − 10x + 15 = 0 have?

A)No real solution
B)One Real solution
c)Two Solutions
D)More than two real solutions
Thanks

1 Answer

7 votes

Answer:

The correct option is (A) No real solution.

Explanation:

The expression provided is a quadratic equation.


8x^(2)-10x+15=0

The roots of a quadratic equation are:


x = ( -b \pm √(b^2 - 4ac))/( 2a )

Here,

a = 8

b = -10

c = 15

The conditions to determine real and complex roots are:

  • If
    b^(2)-4ac<0 then the quadratic equation has two complex roots.
  • If
    b^(2)-4ac>0 then the quadratic equation has two real roots.

Compute the value of
b^(2)-4ac as follows:


b^(2)-4ac=(-10)^(2)-(4* 8*15)\\\\


=100-480\\=-380\\<0

The equation has two complex roots.

Thus, the correct option is (A).

User Cluemein
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