Question

Reduce the fraction to lowest terms. Do not us
- 5jk/35j2k2​

Answer 1

I'm glad you asked!

Explanation:

`((5jk)/(35) j^(2) )(k^(2))`

=

`-(7jk)^(-1)`

Answer 2

`-(7jk)^(-1)`

Explanation:

(Interpreting equation as)

`(-5jk)/(35k^2k^2)`

We can reduce the fraction by dividing the top and the bottom by terms they have in common.

First, lets rewrite both the numerator and denominator in terms of each other.

`(-5jk)/(35j^2k^2)=((-1)(5jk))/((7jk)(5jk))`

If you expand the fraction, you will get exactly what you start with, now this is fine.

As we can see both halves of the fraction have a common term (
`5jk`), so we can divide by this - and the fraction will still be equivalent to as it was before

`(-1)/(7jk)`, or simplified further,

`-(7jk)^(-1)`