Question

In ΔFGH, the measure of ∠H=90°, the measure of ∠G=75°, and FG = 24 feet. Find the length of HF to the nearest tenth of a foot.

Answer 1

HF ≈ 23.2 ft

Explanation:

Using the sine ratio in the right triangle.

sin75° =
`(opposite)/(hypotenuse)` =
`(HF)/(FG)` =
`(HF)/(24)`

Multiply both sides by 24

24 × sin75° = HF , thus

HF ≈ 23.2 ft ( to the nearest tenth )