Question

Please help and show detailed workings for the answers . Tq​

Answer 1

Below,

Explanation:

(a) f is not defined when x = 2 because this would make the denominator = zero.

(i) f-1 is the inverse of f.

Let y = (x + 1)/(x - 2)

y(x - 2) = x + 1

xy - 2y = x + 1

xy - x = 2y + 1

x(y - 1) = 2y + 1

x = (2y +1)/(y - 1)

Replace x by f-1 and y by x , we get:

f-1 = (2x+ 1)(x - 1)

(ii) f-1 is not defined when x = 1 , as this makes the denominator zero.