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A sample of iodine has a volume of 1.0 L at 0.998 atm and 295 K, how grams is in the container?

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Answer:

5.40 g

Step-by-step explanation:

Data: P= 0.998 atm, V= 1.0L, T= 295 K, n= ?

  • use ideal gas law PV= nRT to solve for n. Rearranging the formula gives, n= PV ÷ RT
  • substitute the values into the formula, n= 0.998 atm × 1.0 L ÷ 0.08206 L• atm/mol•K ×295 K
  • all units will cancel and n= 0.0412 mol
  • now solve for mass using n=mass ÷ Molar mass
  • m= n × Mm
  • Mm of iodine= 131 g/mol
  • m= 0.0412mol × 131 g/mol
  • m= 5.40 g
User Craig Anderson
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