Question

The time period of 2 pendulums are 1.22 s and 0.54 s. Calculate the ratio of their lengths.

Answer 1

`~~~~~(T_1)/(T_2)= (1.22)/(0.54)\\\\\\\implies \frac{2\pi \sqrt{(L_1)/(g)}}{2\pi \sqrt\frac{L_2}g}}= 2.259\\\\\\\implies (√(L_1))/(\sqrt g) * (\sqrt g)/(√(L_2)) = 2.259\\\\\\\implies \sqrt{(L_1)/(L_2)} = 2.259\\\\\\\implies (L_1)/(L_2) = 5.104\\\\\\\implies L_1:L_2 = 5.104`