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User Mvandillen
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Answer:


Cu^(2+) + 2e^(-) --> Cu^(0) ||reduction||cathode


2O^(-2) -4e^(-)-->O_(2)^(0)|| oxidation|| anode


Li^(+) +1e^(-)--> Li^(0) || reduction|| cathode


2H^(+) + 2e^(-)-->H_(2)^(0)|| reduction||cathode


Mg^(2+) +2e^(-) --> Mg^(0)|| reduction|| catode


Al^(3+)+3e^(-) --> Al^(0)||reduction||cathode

Metal ions have positive charges, and are attracted to the negative electrode (the cathode) and are reduced during electrolysis.

Non-metal ions have negative charges, and are attracted to the positive electrode (the anode) and are oxidized during electrolysis.

User Morincer
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