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In a quadrilateral ABCD where AB║DC point O is the intersection of its diagonals, ∠A and ∠B are supplementary. Point M∈BC and point K∈AD , so that O∈MK. Prove that

MO≅KO.

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Answer:

The answer to this question can be described as follows:

Explanation:

  • In Additional
    \angleA and B implies, that ABCD is a parallelogram. So, there diagonals AC and BD were intersecting.

  • \angle AKO and CMO are similar to BC, for they are congruent. There are, therefore, congruent
    \angle of MCO and KAO.
  • The AOK and COM triangles are at least identical, so these triangles are congruent because the bisects AC are of BD .
  • Then KO and MO are congruent since they are matching congrue sides, that's why MO≅KO is its points.
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