Question

In a batch of 860 calculators, 9 were found to be defective. What is the probability that a calculator chosen at random will be defective? Write the probability as a percent. Round to the nearest tenth of a percent if necessary.​

Answer 1

Number of calculators n(C)=860

Number of defectives n(D)=9

The probability of a random number being defective=n(D)/n(C)

p=9/860.

converting this to a percentage gives us, 9/860×100%

=90/86

=45/43

=1.0465%

Therefore rounding this number to the nearest tenth gives us 1.0 % since the hundredth digit is 4 which is less than 5.

so, the probability of choosing a random defective calculator is 1.0%