Answer:
first, we need to know the gradient of the line, 2x+3y=15
Gradient of the line is -2/3
from 3y=-2x+15
Y=-2x/3+5
Explanation:
new gradient will be 3/2 since the initial gradient is perpendicular to the new one
therefore, considering the general equation of the line, y-y1=m(x-x1)
where y1=3 and x1=1
we can therefore substitute in the values into the above equation
so, y-3=3/2(x-1)
y-3=3x/2-3/2
2y-6=3x-3
2y-3x=-3+6
2y-3x=3
therefore, the equation of the line perpendicular to line 2x+3y=15 is 3x-2y=-3