Answer:
C2H6O+3O2→2CO2(g)+3H2O
Step-by-step explanation:
Combustion of Ethanol is reaction in which ethanol reacts with oxygen to release carbon dioxide and water molecule.
1. C2H6O+O2→CO2(g)+H2O
Given is the chemical equation of combustion of ethanol but it is not balanced .
To balance it
lets balance carbon first
Since there are two carbon atoms on LHS, to balance it on RHS we add 2 as coefficient on C02 in RHS.
Then we have equation
2. C2H6O+O2→2CO2(g)+H2O
lets balance hydrogen now
Since there are six hydrogen atoms on LHS, to balance it on RHS we add 3 as coefficient on H20 in RHS. On RHS there are two hydrogen atoms. When 3 is added as coefficient then number of hydrogen atoms becomes 6 (3*2 = 6)
Then we have equation given below
2. C2H6O+O2→2CO2(g)+3H2O
lets balance oxygen now now
on RHS
no. of atoms of oxygen on RHS in 2CO2 = 2*2 = 4
no. of atoms of oxygen on RHS in 3H2O = 3*1 = 3
Total no. of atoms of oxygen on RHS = 4+3 = 7
no. of atoms of oxygen on LHS in C2H6O = 1*1 = 1
no. of atoms of oxygen on LHS in O2 = 1*2 = 2
Total no. of atoms of oxygen on LHS = 2+1 = 3
We cannot make changes in C2H6O as atoms of carbon and hydrogen are balanced so we have to balance the atoms of O2 on RHS.
We add coefficient 3 to O2 on LHS which makes no of atoms in O2 to be 6 (3*2 = 6)
Thus total atoms of oxygen on RHS becomes 7( one atom of oxygen in C2H6O and 6 atoms in O2)
Writing it we have equation given below.
C2H6O+3O2→2CO2(g)+3H2O
This is the solution to the problem.