Question

Which of the following reactions occur at the negative electrode if a 1 M NaCl (aq) solution is used as a plating solution? Select a balanced reduction half-reaction below for your answer. Hint - Na metal cannot be produced in aqueous solutions. Na+ + e- → Na (s) Cl2 + 2 e- → 2 Cl- (aq) H2O + e- → 1/2 H2 (g) + OH- (aq) H2O → H+ (aq) + OH- (aq) Na + e- → Na- (aq)

Answer 1

The reduction half-reaction that occurs at the negative electrode in a 1M NaCl(aq) solution is 2H₂O(1) + 2e¯¯ → H₂(g) + 2OH(aq). This means that water molecules pick up electrons from the electrode and undergo reduction to form hydrogen gas (H₂) and hydroxide ions (OH¯).

Step-by-step explanation:

The reduction half-reaction that occurs at the negative electrode when a 1M NaCl(aq) solution is used as a plating solution is:

2H₂O(1) + 2e¯¯ → H₂(g) + 2OH(aq)

This means that water molecules pick up electrons from the electrode and undergo reduction to form hydrogen gas (H₂) and hydroxide ions (OH¯).