Question

Calculate the de Broglie wavelength of an electron traveling at 2.0 x 10^8 m/s (me = 9.1*10^-31 kg).

6.9 x 10^-6 m
O 2.8 x 10^11 m
O 3.6 * 10^12 m

Answer 1

`\lambda=3.64* 10^(-12)\ m`

Step-by-step explanation:

We have,

Speed of an electron is
`2* 10^8\ m/s`

It is required to find the De Broglie wavelength of electron. The formula for the De- Broglie wavelength is given by :

`\lambda=(h)/(mv)`

h is Planck's constant

m is mass of an electron

Plugging all the values we get :

`\lambda=(6.63* 10^(-34))/(9.1* 10^(-31)* 2* 10^(8))\\\\\lambda=3.64* 10^(-12)\ m`

So, the De-Broglie wavelength of an electron is
`3.64* 10^(-12)\ m`