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The following data for a random sample of banks in two cities represent the ATM fees for using another​ bank's ATM. Compute the range and sample standard deviation for ATM fees for each city. Which city has the most dispersion based on​ range? Which city has more dispersion based on the standard​ deviation? City A 1.001.00 1.001.00 1.501.50 1.251.25 1.501.50 City B 2.502.50 1.001.00 1.501.50 0.000.00 2.002.00 The range for city A is ​$0.50.5. The range for city B is ​$2.52.5. The standard deviation for city A is ​$0.250.25. ​(Round to the nearest cent as​ needed.) The standard deviation for city B is ​$0.960.96. ​(Round to the nearest cent as​ needed.) Which city has the most dispersion based on​ range? A. City Upper BB​, because it has a higher range. B. City Upper AA​, because it has a higher range. C. City​ A, because it has a lower range. D. City​ B, because it has a lower range. Which city has the most dispersion based on standard​ deviation?

User NizarETH
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Answer:

Option A, City B has more dispersion than City A based on range

City B has more dispersion than City A based on standard deviation

Explanation:

City A $1.00 $1.50 $1.25 $1.50 $1.25

Range = highest - lowest = $1.50 - $1.00

The range for city A is ​$0.50

The standard deviation for city A is ​$0.25

City B $2.00 $1.50 $1.50 $0.00 $2.00

The range for city B is ​$2.5

The standard deviation for city B is ​$0.96

User Skabbes
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