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Three consecutive numbers have a sum of 36. What are the numbers?

1 Answer

5 votes

Answer:

11,12,13

Explanation:

x is the first number

x+1 is the second number

x+2 is the third number

x+ x+1+x+2 = 36

Combine like terms

3x+3 = 36

Subtract 3 from each side

3x+3-3= 36-3

3x = 33

Divide by 3

3x/3 = 33/3

x = 11

The numbers are 11, 11+1, 11+2

11,12,13

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