Answer:
A = 728J
Step-by-step explanation:
Mass of substance = 30g
Specific capacity of copper = 0.385J/g°C
Initial temperature (T1) = 27°C
Final Temperature (T2) = 90°C
Heat energy (Q) = ?
Heat Energy (Q) = Mc∇T
Q = heat energy
M = mass of the substance
C = specific heat capacity of the substance
∇T = change in temperature of the substance = T2 - T1
Q = mc∇T
Q = mc×(T2 - T1)
Q = 30 × 0.385 × (90 - 27)
Q = 11.55 × 63
Q = 727.65J
The heat energy required to raise 30g of copper sample from 27°C to 90° is 728J