Answer:
The correct answer is 0.25 moles NH₃
Step-by-step explanation:
First, we need to know the chemical equation for NH₃ formation from H₂. The balanced chemical reaction involved in NH₃ obtention is the following:
N₂(g) + 3 H₂(g) → 2 NH₃(g)
According to this, 2 moles of NH₃ are formed from 3 moles of H₂. We can write that estequiometrical relation as: 2 moles NH₃/ 3 moles H₂.
From the problem, we have to calculate how many moles of NH₃ are produced from 0.37 moles H₂. So, we can simply multiply the number of moles of H₂ to obtain by the convertion factor:
0.37 moles H₂ x 2 moles NH₃/ 3 moles H₂= 0.246 moles NH₃ ≅ 0.25 moles NH₃
Thus, 0.25 moles of NH₃ will be obtained.