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What is an equation of the line perpendicular to 5x−4y=10 that passes through the point (−1,−6) ?

User Overactor
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1 Answer

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Answer:

y = -4/5x-34/5

Explanation:

1. Put into slope-intercept form: 5x-4y = 10 ⇒ 4y = 5x-10 ⇒ y = 5/4x - 5/2

2. A perpendicular slope is the negative reciprocal of the original slope. ⇒ m = -4/5

3. Make a general solution using the new slope: y = -4/5x + b

4. Plug in the point (-1,-6) and solve for b: -6 = -4/5(-1) + b ⇒ -6-(4/5) = b ⇒

b = -34/5

5. Put b in the general solution to find the particular solution: y = -4/5x-34/5

User Vladimir Panchenko
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