60.0k views
3 votes
Byron bought a keyless entry door lock that has the digits 0 through 9 on the keypad. He wants to choose a three-digit entry code. How many different combinations are possible, if the digits can be repeated?

27
30
729
1,000

2 Answers

1 vote

Answer:

1000

Explanation: He wants to choose a three-digit entry code. he has the digits 0 through 9 on the keypad. so you have 10 choices on the first number 10 choices on the second number and 10 choices on the third number.

10 * 10 * 10 = 1000

User Xiaoke
by
5.0k points
4 votes

Answer:

1000

Step-by-step explanation:

There are 10 possible choices for the first number, 10 for the second, and 10 for the third. Multiplying all of this together, you get 10*10*10=1000 possible combinations. Hope this helps!

User Daniel Golden
by
4.7k points