Question

Calculate the concentration of hydrogen ions, H+, in a solution with a pOH of 4.223

Answer 1

Concentration of hydrogen ion is

`1.671 * 10^(-10)`

Step-by-step explanation:

pOH of solution
`= 4.223`

The concentration of OH ions is to be derived first

As we know-

pOH
`= - log [ OH^-]`

Substituting the given values, we get -

`4.223 = - log [OH^-]\\`

Taking antilog on both sides we get -

OH- concentration
`= (1)/(10^(4.223))`

OH- concentration
`= 5.984 * 10^(-5)`

As we know tha

Pkw
`= P[H^+] + P[OH^-]`

`14 = P[H^+] + 4.223\\P[H^+] = 14 - 4.223\\P[H^+] = 9.777`

Concentration of hydrogen ion is

`9.777 = - log{H^+]\\log{H^+] = -9.777\\{H^+] = (1)/(10^(-9.777)) \\{H^+] = 1.671 * 10^(-10)`

Concentration of hydrogen ion is

`1.671 * 10^(-10)`