Question

Solve the following equation algebraically:

2 x squared = 50
a.
Plus-or-minus 0.2
b.
Plus-or-minus 7.07
c.
Plus-or-minus 5
d.
Plus-or-minus 12.5

Answer 1

Step-by-step explanation: in short the answer is C +5

Answer 2

C. ±5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

• Equality Properties
• Solving Quadratics
• Multiple Roots

Explanation:

Step 1: Define

2x² = 50

Step 2: Solve for x

1. Divide 2 on both sides: x² = 25
2. Square root both sides: x = ±5

Step 3: Check

Plug in x into the original equation to verify it's a solution.

x = 5

1. Substitute in x: 2(5)² = 50
2. Exponents: 2(25) = 50
3. Multiply: 50 = 50

Here we see that 50 does indeed equal 50.

∴ x = 5 is a solution to the equation.

x = -5

1. Substitute in x: 2(-5)² = 50
2. Exponents: 2(25) = 50
3. Multiply: 50 = 50

Here we see that 50 does indeed equal 50.

∴ x = -5 is a solution to the equation.