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Write the equation of the circle with a center at (- 2, - 8) and a radius of sqrt(10) .

User Blackbelt
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1 Answer

6 votes

Answer:

(x + 2)^2 + (y + 8)^2 = 10

Explanation:

The general equation of a circle with center at (h, k) and radius r

is (x - h)^2 + (y - k)^2 = r^2. If the center is at (-2, -8) and the radius is √10, then this equation becomes:

(x + 2)^2 + (y + 8)^2 = 10

User Muthulakshmi M
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