Question

8. (3x-5) mZS = 0 MZR = Р T con A (117 Bux+5)* S
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Answer 1

95°, 110°

Explanation:

Since we're dealing with a cyclic quadrilateral ,

m<T + m<R 180°

7y + 11y = 180°

18y = 180°

y = 10°

Also,

m<S + m<U = 180°

3x+5+3x-5= 180°

6x = 180°

x = 30°

m<S = 3x+5 = 3(30)+5

= 95°

m<R = 11y = 11(10)

= 110°

Answer 2

Given -

• m∠R = (11y)°
• m∠S = (3x + 5)°
• m∠T = (7y)°
• m∠U = (3x - 5)°

To find -

• m∠R
• m∠S

(nullifying x and y)

Explanation -

As we know this is a cyclic quadrilateral and it's either pair of the opposite angles sum up to 180°.

Therefore,

m∠S + m∠U = 180° ---(1)

m∠R + m∠T = 180° ---(2)

Solution -

Substituting the values of the measure of angles in (1)

➜ m∠S + m∠U = 180°

➜ (3x + 5)° + (3x - 5)° = 180°

➜ 6x = 180°

➜ x = 180/6

➜ x = 30

Therefore, m∠S = (3x + 5)° = {3(30)+5}° = (90+5)°

m∠S = 95°

Substituting the values of the measure of angles in (2)

➜ m∠R + m∠T = 180°

➜ (11y)° + (7y)° = 180°

➜ 18y = 180°

➜ y = 180/18

➜ y = 10

Therefore, m∠R = (11y)° = (11×10)° = 110°