Answer:0.5176
Explanation:
Given
We need to draw 5 cards out of 52 cards
So no of ways of choosing 5 cards out of 52 is
![^(52)C_(5)](https://img.qammunity.org/2021/formulas/mathematics/college/verzezzrs2e3106w1xknwkv8ouupfoi503.png)
Now to choose 3 cards of same suit
First we have to choose 1 suit out of 4 which can be done in
ways
Now choosing 3 out of 13 cards is
![^(13)C_3](https://img.qammunity.org/2021/formulas/mathematics/college/rfjopack827ubwk0hin5sy1l2s386t8i4r.png)
and remaining two cards can be chosen in
![^(49)C_2](https://img.qammunity.org/2021/formulas/mathematics/college/exq86whir0inrcrrxjwkpfnp6oohmjijsy.png)
So total no of ways are
![=^4C_1* ^(13)C_3* ^(49)C_2](https://img.qammunity.org/2021/formulas/mathematics/college/otd8lgf35ix046daq6483nz9wwn8fh0k3b.png)
So probability
![=(^4C_1* ^(13)C_3* ^(49)C_2)/(^(52)C_(5))](https://img.qammunity.org/2021/formulas/mathematics/college/8q218k73geygo7y92ciptdgm3fqvzvrp5c.png)
![P=(4* 26* 11* 49* 24)/(2598960)](https://img.qammunity.org/2021/formulas/mathematics/college/k1dycpsjd13112ss05ouhztutdovatloiq.png)
![P=0.5176](https://img.qammunity.org/2021/formulas/mathematics/college/51l5vlha3l6jp96tdwbmg02pbk3aczo7ju.png)