1 Answer

Raja Jaganathan · Answer 1 · 2021-03-31T05:59:42+0000

Answer:

3.48cm³ (approximated)

Explanation:

The maximum water that bowl can hold = The volume of the bowl

$\boxed{ \mathsf{volume \: of \: bowl = (2)/(3) * \pi \: r {}^(3) }}$

Radius is half of diameter.

Given -

From the given data we can derive that the radius of the hemispherical bowl is 5cm (10/2)

Putting the known values into the formula to get the value of the volume of bowl :

$\mathsf{volume = (2)/(3) * \: 3.14 \: * {5}^(3) }$

= 3.48888cm³

= 3.48cm³

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