Question

Factor to solve each equation. Does the equation have a solution of x = 2? Select Yes or No for each.

Answer 1

4x^2 - 16 = 0

<=> (2x)^2 - 4^2 = 0

<=> (2x + 4)(2x - 4) = 0

<=> x = -2 or x = 2

=> YES

x^2 - 4x + 4 = 0

<=> (x - 2)^2 = 0

<=> x = 2

=> YES

4x^2 + 16x + 16 = 0

<=> 4(x^2 + 4x + 4) = 0

<=> 4(x + 2)^2 = 0

<=> x = -2

=> NO

Hope this helps!

:)