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What is the solution set of (x-2)(x-3)=2

User Fredo
by
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1 Answer

3 votes

Answer:

x= 1 or x=4

Explanation:

(x-2)(x-3)=2

Expand the equation to form

x^2-3x-2x+6=2

X^2-3x-2x+6-2=0

(x-4)(x-1)=0

Therefore ,

x-4=0 or x-1=0

ans is : x=4 or x=1

User Bahadur Singh Deol
by
4.5k points