The circle below is centered at (3, 1) and has a radius of 2. What is its equation? HA A. (x-3)2 + (y - 1)2 = 2 B. (x - 1)2 + (y - 3)2 = 4 C. (x-1)2 + (y - 3)2 = 2 D. (x-3)2 + (- 1)2 = 4 Help - QAmmunity.org

The circle below is centered at (3, 1) and has a radius of 2. What is its equation? HA A. (x-3)2 + (y - 1)2 = 2 B. (x - 1)2 + (y - 3)2 = 4 C. (x-1)2 + (y - 3)2 = 2 D. (x-3)2 + (- 1)2 = 4 Help

asked Mar 9, 2021 45.5k views

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