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Liam opened a savings account and deposited $6000. The account earns 5% in interest annually. He makes no further deposits and does not withdraw any money. In t years, he has $8865 in this account.

Write an equation in terms of t that models the situation.

User Ritlew
by
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2 Answers

7 votes

Answer:

6000*1.5^t=8865

Explanation:

Liam starts with 6000 dollars. Since 5% is 5% OF 6000, the expression would be 6000+5%*6000. When we distribute 6000, we get: 6000(1.5). And since every year we multiply by 1.5, we should get: 6000*1.5^t. t years later=8865. So our expression would become: 6000*1.5^t=8865

User Vince Gonzales
by
3.9k points
5 votes

Answer:
8865=6000(1+(5* t)/(100))

Explanation:

Given

Liam deposited
P=\$\ 6000

Rate of interest is
R=5\ \%

If the amount after t years is
A=\$\ 8865

Simple interest is given by


S.I.=(P* R* t)/(100)

And amount is


A=P+S.I.


A=P(1+(R* t)/(100))

Substituting values we get


8865=6000(1+(5* t)/(100))


1.4775=1+(5* t)/(100)


0.4775(5* t)/(100)


5t=47.75


t=(47.75)/(5)=9.55\ years

User Sivakanesh
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4.3k points