Answer:
THE FINAL TEMPERATURE OF THE SOLUTION IS 31.4°C.
Step-by-step explanation:
To solve for the final temperature of the solution formed, we must first calculate the quantity of heat given off by the reaction.
From the equation of the reaction, it will be observed that ΔH is negative meaning that the heat is given off from the reaction.
Quantity of heat = ΔH * number of mole of NaOH
So, we calculate the number of moles of NaOH used by dividing the mass of NaOH by the relative molecular mass.
RMM of NaOH = 40 g/mol
Number of mole = mass / RMM
n = 1.52 / 40 = 0.038 moles.
So therefore, Q =ΔH * n (NaOH)
Q = 44.5 * 0.038
Q = 1.691 kJ
We can now solve for the final temperature by using the formula assuming that the specific heat of water is 4 2 J/g °C
Q = mc (T2 - T1)
Rearranging,
T2 = Q / m c + T1
T2 = 1.691 kJ / 35.5 g * 4.2 J/g°C + 20.1° C
T2 = 1.691* 10^3 J / 149.1 J ° C + 20.1 °C
T2 = 0.0113 * 10^3 + 20.1
T2 = 11.3 + 20.1 ° C
T2 = 31.4 °C
The final temperature of the solution formed is 31.4 °C.