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What is the missing constant term in the perfect square that starts with x2+18xx^2+18xx2+18xx, squared, plus, 18, x ?

2 Answers

7 votes

Answer:

This is written as a perfect square as
(x+9)^2

The constant term required therefore is 81.

Explanation:

Given that;

The expression
x^2+18x

we follow the following steps.

Divide the coefficient of x by 2

Coefficient of


x = 18, \\\\18 /2=9

Square 9

9² = 81

The expression goes


x^2+18x+81

This is written as a perfect square as
(x+9)^2

The constant term required therefore is 81.

User Peter Mularien
by
6.1k points
3 votes

Answer:

81

Explanation:

Given the expression:
x^2+18x

To make it a perfect square, we follow the following steps.

Divide the coefficient of x by 2

  • Coefficient of x=18, 18/2=9

Square It

  • 9 X 9=81

Add it to the expression


  • x^2+18x+81

This is written as a perfect square as:
(x+9)^2

The constant term required therefore is 81.

User Alex Kopachov
by
5.2k points