Question

What is the general from of the equation of a circle with center at (a , b ) and radius of length m?

Answer 1

`(x - a)^(2) + (y - b)^(2) = m^(2)`

Explanation:

The equation of a circle has the following format:

`(x - x_(0))^(2) + (y - y_(0))^(2) = r^(2)`

In which r is the radius(half the diameter) and the centre is the point
`(x_(0), y_(0))`

In this question:

Center (a,b), so
`x_(0) = a, y_(0) = b`

Radius m

Then

`(x - a)^(2) + (y - b)^(2) = m^(2)`