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What is the probability of getting an even sum less than 7 on one roll of 2 fair cubes

1 Answer

2 votes

Answer:


(1)/(4)

Explanation:

When you roll two fair cubes once, the outcomes are given below:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total Number of Outcomes=36

The sum of the outcomes less than 7 are:

2,3,4,5,6

3,4,5,6

4,5,6

5,6

6

Number of Even sum less than 7=9

Therefore:

Probability of getting an even sum less than 7


=(9)/(36)=(1)/(4)

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