Question

The equation for a circle is (x-2)2+(y+3)2=9, what is the center of the circle?​

Answer 1

(2, -3)

Explanation:

Compare the given (x-2)2+(y+3)2=9 to the standard equation

(x - h)^2 + (y - k)^2 = r^2.

It becomes obvious that h = 2, k = -3 and r = 3.

The center of this circle is (h, k): (2, -3).