Question

What is the volume of a gas at 0.43 atm, if it had a volume of 720 mL at a pressure of 698 mm Hg?

Answer 1

The answer to your problem would be 0.337L or 333mL

This is due to the equation that is used:

INITIAL PRESSURE x INITIAL VOLUME = FINAL PRESSURE X FINAL VOLUME.

Step-by-step explanation:

We use this equation because said gas assumes that it behaves like an ideal gas, therefore its number of moles remains constant and the constant number of ideal gases R on both sides would be simplified, taking as a final equation the one we wrote above.

Your initial pressure, which is the one with which the gas starts the reaction, is 0.43 atm, your final pressure would be 698 mmHg (mmHg means millimeter of mercury and it is a different unit to express the pressure, here you would have to make the passage to atmospheres considering that an atmosphere is 760 mmHg) .. and lastly the initial volume is 720 ml, so solving for the unknown final volume would take out its value.

I hope I was clear, anything you can consult me again

Answer 2

0.337L or 333mL

Step-by-step explanation:

P1 = 0.43atm

V1 = 720mL = 0.72mL

P2 = 698mmHg

To solve this question, we'll have to convert one of the unit of pressure so that our answer can be correct.

1atm = 760mmHg

X atm = 698mmHg

X = (698 × 1) / 760

X = 0.918atm

Data:

P1 = 0.43atm

P2 = 0.918atm

V1 = 0.72L

V2 = ?

Applying Boyle's law which states that the pressure of a fixed mass of gas is inversely proportional to its volume provided that temperature remains constant,

Mathematically,

P = k / V, k = PV

P1 × V1 = P2 × V2 =......Pn×Vn

P1 × V1 = P2 × V2

V2 = (P1 × V1) / P2

V2 = (0.43 × 0.72) / 0.918

V2 = 0.3096 / 0.918

V2 = 0.337L

The final volume of the gas is 0.337L