Question

A chemistry teacher needs to make 10 L of 36% sulphuric acid solution. The acid solutions available are 30% sulphuric acid and 50% sulphuric acid, by volume. How many litres of each solution must be mixed to make the 36% solution?

Answer 1

Answer:7 L and 3 L

Explanation:

Given

Solution
`1` has
`30\%` sulphuric acid by volume

Solution
`2\ \text{has}\ 50\%` sulphuric acid by volume

final solution is
`10\ L` of
`36\%` sulphuric acid

Suppose there is
`V_1\ L` and
`V_2\ L` of sulphuric acid of solution
`1` and
`2` respectively

So, quantity of acid before and after remains same

`0.3* V_1+0.5* V_2=0.36* 10`

`3V_1+5V_2=36\quad \ldots(i)`

and total mixture before and after remains same i.e.

`V_1+V_2=10\quad \ldots(ii)`

Solving
`(i)` and
`(ii)` we get

So we get
`V_1=7\ L` and
`V_2=3\ L`

So, 7 liters from solution 1 and 3 liters from solution 2