Question

What is the inverse of Y = 2x^2 - 8

Answer 1

`y = \pm \sqrt{(x+8)/(2) }`

Explanation:

When you're writing the inverse equation, switch the position of the x and y and then solve for y.

`x = 2y^(2) - 8 \\2y^(2) = x+8 \\y^(2) = (x+8)/(2)\\ y = \pm \sqrt{(x+8)/(2) }`