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Last year Oscar bought a packet of biscuits every week and found 30 of 3 these packets contained broken biscuits. What is the relative frequency

of this event? Answer correct to 2 decimal places. Explain why you
chose the numbers in your calculation

1 Answer

3 votes

Answer:

Relative Frequency = 0.58

Explanation:

Given

A packet of biscuit every week

Number of packets that contains broken biscuits = 30

Required

Relative Frequency

First, the total packet of biscuit bought needs to be calculated.

The question says Oscar bought a packet every week of the year and there are 52 weeks in a year.

This means that Oscar bought 52 packets of biscuits.

So, we can conclude that 30 out 52 packets contains broken biscuits.

The relative frequency is then calculated as this;

Relative Frequency = Number of packets that contains broken biscuits divided by total number of packets.

Relative Frequency = 30/52

Relative Frequency = 0.5769230769

Relative Frequency = 0.58 (Approximated).

Hence, the relative frequency of the broken packets of biscuits is 0.58

User JayDeeEss
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