Question

You are monitoring the sound intensity and sound intensity level from two different sources (#1 and #2) of sound at a specific site. You determine that at that site, source #1 has a sound intensity of 38.3 W/m2 and source 2 has an intensity level that is 2.6 dB greater than the intensity level of source 1. Determine the sound intensity of source #2. W/m2

Answer 1

To determine the sound intensity of source 2, we need to find the intensity level of source 2 first.

Step-by-step explanation:

To determine the sound intensity of source 2, we need to find the intensity level of source 2 first. Since the intensity level of source 2 is 2.6 dB greater than the intensity level of source #1, we can write the equation:

Intensity level of source 2 = Intensity level of source #1 + 2.6 dB

Next, we can convert the intensity level back into intensity using the formula: Intensity = 10^(intensity level/10)

By substituting the given intensity level of source #1 and solving for the intensity of source 2, we can find the sound intensity of source 2.

Answer 2

The sound intensity of source #2 is 38.3 W/m²

Step-by-step explanation:

Given;

sound intensity of source #1, I₁ = 38.3 W/m²

sound intensity of source #2, I₂ = 2.6 dB greater than 38.3 W/m²

To determine he sound intensity of source #2 in W/m², we must convert 2.6 dB to sound intensity in W/m².

`10log(I (W/m^2))/(I_o) = I (dB)\\\\10log(I )/(1*10^(-12)) = 2.6\\\\log((I )/(1*10^(-12)))^(10) = 2.6\\\\10^(2.6) = ((I )/(1*10^(-12)))^(10) \\\\10^{(2.6)/(10)} = (I )/(1*10^(-12))\\\\1.8197 = (I )/(1*10^(-12))\\\\I = 1.8197 *1*10^(-12) = 1.8197 *10^(-12) \ W/m^2`

Thus, sound intensity of source #2 = 38.3 W/m² + 1.8197 x 10⁻¹² W/m² = 38.3 W/m²

Therefore, the sound intensity of source #2 is 38.3 W/m²