Question

I need help with this Geometry problem​

Answer 1

A, D, E

Explanation:

BE is the perpendicular bisector of DF. So E is the midpoint of DF, and ∠DEB = 90°. Therefore, A and E are true.

Since DE = EF, and EB = EB, and ΔDEB and ΔFEB are right triangles, they are congruent by SAS. Therefore, BD = BF, so D is true.