Solve the equation on the interval [0, 2pi). 3 sin x = sin x + 1

Janay asked Jan 7, 2023

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9 votes

Solve the equation on the
interval [0, 2pi).
3 sin x = sin x + 1

Janay asked Jan 7, 2023

by Janay

2.6k points

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21 votes

Answer:

π/6 , 7π/6

Explanation:

3sinx = sinx + 1 ⇒ 2sinx = 1 ⇒ sinx = 1/2

At which value(s) of x does sinx equal 1/2?

x = arcsin(1/2) at π/6 and 5π/6

Gintautas answered Jan 11, 2023

2.9k points

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