Question

H(1) = -5.3

h(n) = h(n-1)•(-11)

Find an explicit formula for h(n).

Answer 1

first term: -5.3

common factor: -11

This is a geometric sequence hence the equation is the (first term)*
`(commonfactor)^(n-1)`.

So, the equation is -5.3*
`(-11)^(n-1)`

I did it on khan academy:

Answer 2

`h(n) = (-5.3)\cdot (-11)^(n-1)`,
`\forall n \in \mathbb{N}`

Explanation:

The explicit formula for
`h(n)` is:

`h(n) = (-5.3)\cdot (-11)^(n-1)`,
`\forall n \in \mathbb{N}`