Question

How many liters of H2 can form when 4.53 x 10^3 mL C5H8 form?

Answer 1

`V_(H_2)=2.02x10^3LH_2`

Step-by-step explanation:

Hello,

In this case, we must consider the original reaction:

`C_5H_(12)\rightarrow C_5H_8+2H_2`

Which is a dehydrogenation reaction wherein the density of hydrogen (molar mass 2 g/mol) is 0.0899 g/L and the density of pentyne (molar mass 68 g/mol) is 0.681 g/mL. In such a way, given the formed volume of pentyne we can compute the volume of hydrogen that is produced by applying stoichiometry based on the 2:1 mole ratio between hydrogen and pentyne:

`V_(H_2)=4.53x10^3LC_5H_8 *(0.681gC_5H_8)/(1LC_5H_8) *(1molC_5H_8)/(68gC_5H_8)*(2molH_2)/(1molC_5H_8) *(2gH_2)/(1molH_2)*(1LH_2)/(0.0899gH_2) \\\\V_(H_2)=2.02x10^3LH_2`

Best regards.