Question

Ionic equation for Sr3(PO4)2 and its solubility product (Ksp)?​

Answer 1

`Sr_3(PO_4)_2(s)\rightleftharpoons 3Sr^(+2)(aq)+2(PO_4)^(-3)(aq)`

`Ksp=[Sr^(+2)]^3[(PO_4)^(-3)]^2`

Step-by-step explanation:

Hello,

In this case, for strontium phosphate, we find an ionic equation for its dissociation as shown below:

`Sr_3(PO_4)_2(s)\rightleftharpoons 3Sr^(+2)(aq)+2(PO_4)^(-3)(aq)`

Next, the solubility product is found by applying the law of mass action, considering that the solid salt is not considered but just the aqueous species due to heterogeneous equilibrium:

`Ksp=[Sr^(+2)]^3[(PO_4)^(-3)]^2`

Best regards.