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Solve for x

khan academy solve similar triangles advanced

User Brian Burg
by
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1 Answer

6 votes

Answer:

x = 10/3

Explanation:

The question is incomplete without the diagram as this would enable us solve for x. Find attached the diagram used for solving the question.

We can tell from the question we are to compare two triangles drawn together (smaller one drawn in a bigger one) using similar triangles.

Using similar triangles to solve for x,

∆ABC = ∆ADE

∠CBA = ∠EDA = 90°

Let's relate the ratio of their corresponding sides.

(Adjacent/opposite) in ∆ABC

= (Adjacent/opposite) in ∆ADE

AB/CB = AD/ED

AB = 6

CB = 2

AD = AB + BD = 4+6 = 10

ED = x

6/2 = 10/x

3 = 10/x

3x = 10

x = 10/3

Solve for x khan academy solve similar triangles advanced-example-1
User TonyWilk
by
6.9k points