Answer:
21% probability you will hit a green light on monday and a red light on tuesday
Explanation:
When two events, A and B, are independent, we have that:
![P(A \cap B) = P(A) * P(B)](https://img.qammunity.org/2021/formulas/mathematics/college/iw43v4qame1j448cua3s6z7v0zbww216j8.png)
In this problem, we have that:
Event A: Green light on monday.
Event B: Red light on tuesday.
The probability that we encounter a green light at the corner of college and main is 0.35
This means that
![P(A) = 0.35](https://img.qammunity.org/2021/formulas/mathematics/college/9rzf7lusvw94ilrctzev6u397kdwn94zdz.png)
The probability that we encounter a red light is 0.61:
This means that
![P(B) = 0.61](https://img.qammunity.org/2021/formulas/mathematics/college/rj6d3ojbw2iqp5656mmy5pe21psnc522nl.png)
These events are independent, that is, the light color on Tuesday is independent of the color on Monday. So
![P(A \cap B) = P(A) * P(B) = 0.35 * 0.6 = 0.21](https://img.qammunity.org/2021/formulas/mathematics/college/1djztp3dnxi3h6u9q35kdy0zqhwyfk0z3x.png)
21% probability you will hit a green light on monday and a red light on tuesday